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Popular >

extreme f(x)=x^4-4x-8

Solution

extreme points

f (x) = x^{4} - 4 x - 8

Solution

Minimum (1, - 11)

Solution steps

f^{'} (x) = 4 x^{3} - 4

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{4} - 4 x - 8 : - 11

Minimum (1, - 11)

Popular Examples

extreme f(x)=-2x^3+83x^2+212 extreme points

f (x) = - 2 x^{3} + 83 x^{2} + 212

extreme f(x)=-x^3+27-61 extreme points

f (x) = - x^{3} + 27 - 61

extreme f(x,y)=x^3+3xy^2+xy^3-5y-4 extreme points

f (x, y) = x^{3} + 3 x y^{2} + x y^{3} - 5 y - 4

extreme f(x,y)=2x^4-x^2+3y^2 extreme points

f (x, y) = 2 x^{4} - x^{2} + 3 y^{2}

extreme f(x)=2x^2+4x+3 extreme points

f (x) = 2 x^{2} + 4 x + 3

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4-4x-8 ?
The extreme f(x)=x^4-4x-8 is Minimum(1,-11)