What is the extreme f(x)= 2/9 x^3+2x^2-2 ?

The extreme f(x)= 2/9 x^3+2x^2-2 is Maximum(-6,22),Minimum(0,-2)

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extreme f(x)= 2/9 x^3+2x^2-2

extreme points

f (x) = \frac{2}{9} x^{3} + 2 x^{2} - 2

Maximum (- 6, 22), Minimum (0, - 2)

Solution steps

f^{'} (x) = \frac{2 x ^{2}}{3} + 4 x

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 6

into

\frac{2}{9} x^{3} + 2 x^{2} - 2 : 22

Maximum (- 6, 22)

Plug

x = 0

into

\frac{2}{9} x^{3} + 2 x^{2} - 2 : - 2

Minimum (0, - 2)

Maximum (- 6, 22), Minimum (0, - 2)

f (x) = x (40 - 2 x)^{2}

y = \frac{x}{( x - 2 ) ^{2}}

\frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 3

f (x) = 10000 e^{0.84 (x - 1.4)^{2}}

f (x, y) = 3 x^{2} y - y

What is the extreme f(x)= 2/9 x^3+2x^2-2 ?
The extreme f(x)= 2/9 x^3+2x^2-2 is Maximum(-6,22),Minimum(0,-2)