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Popular >

extreme f(x)=-x^2+x

Solution

extreme points

f (x) = - x^{2} + x

Solution

Maximum (\frac{1}{2}, \frac{1}{4})

Solution steps

f^{'} (x) = - 2 x + 1

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- x^{2} + x : \frac{1}{4}

Maximum (\frac{1}{2}, \frac{1}{4})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+x ?
The extreme f(x)=-x^2+x is Maximum(1/2 , 1/4)