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Popular >

extreme f(x)=7+5x+x^2

Solution

extreme points

f (x) = 7 + 5 x + x^{2}

Solution

Minimum (- \frac{5}{2}, \frac{3}{4})

Solution steps

f^{'} (x) = 2 x + 5

Find intervals:

Decreasing

: - \infty < x < - \frac{5}{2},

Increasing

: - \frac{5}{2} < x < \infty

Plug

x = - \frac{5}{2}

into

7 + 5 x + x^{2} : \frac{3}{4}

Minimum (- \frac{5}{2}, \frac{3}{4})

Popular Examples

extreme f(x)=(x+5)e^{-2x}extreme points

f (x) = (x + 5) e^{- 2 x}

extreme f(x,y)=x^2+2xy+x^2 extreme points

f (x, y) = x^{2} + 2 x y + x^{2}

extreme f(x,y)=y+xy^4 extreme points

f (x, y) = y + x y^{4}

extreme f(x)=x^4+32x^2 extreme points

f (x) = x^{4} + 32 x^{2}

extreme f(x)=(x^4-32x^2)/9 extreme points

f (x) = \frac{x ^{4} - 32 x ^{2}}{9}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=7+5x+x^2 ?
The extreme f(x)=7+5x+x^2 is Minimum(-5/2 , 3/4)