What is the extreme f(x)=100x-(800+50x+2x^2) ?

The extreme f(x)=100x-(800+50x+2x^2) is Maximum(25/2 ,-975/2)

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extreme f(x)=100x-(800+50x+2x^2)

extreme points

f (x) = 100 x - (800 + 50 x + 2 x^{2})

Maximum (\frac{25}{2}, - \frac{975}{2})

Solution steps

f^{'} (x) = - 4 x + 50

Find intervals:

Increasing

: - \infty < x < \frac{25}{2},

Decreasing

: \frac{25}{2} < x < \infty

Plug

x = \frac{25}{2}

into

100 x - (800 + 50 x + 2 x^{2}) : - \frac{975}{2}

Maximum (\frac{25}{2}, - \frac{975}{2})

\frac{π}{24} sec^{2} (\frac{π x}{24})

f (x) = 9 x^{\frac{2}{3}} - x, 0 \leq x \leq 729

f (x) = \frac{x ^{2} + 4}{4 x}, 1 \leq x \leq 10

23 x + 11 y + 20

f (x) = (x^{2} - 2 x y + 3 y^{2})

What is the extreme f(x)=100x-(800+50x+2x^2) ?
The extreme f(x)=100x-(800+50x+2x^2) is Maximum(25/2 ,-975/2)