en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2-18ln(x)

Solution

extreme points

f (x) = x^{2} - 18 ln (x)

Solution

Minimum (3, 9 - 18 ln (3))

Solution steps

f^{'} (x) = 2 x - \frac{18}{x}

Find intervals:

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

x^{2} - 18 ln (x) : 9 - 18 ln (3)

Minimum (3, 9 - 18 ln (3))

Popular Examples

extreme f(x,y)=5x^2+5y^2+20x-10y extreme points

f (x, y) = 5 x^{2} + 5 y^{2} + 20 x - 10 y

extreme f(x,y)=xy+pi/8 x^2 extreme points

f (x, y) = x y + \frac{π}{8} x^{2}

extreme f(x)=-4+x-x^2 extreme points

f (x) = - 4 + x - x^{2}

solvefor k,p=c*e^{k*h}solve for

k, p = c \cdot e^{k \cdot h}

extreme x^8(x-7)^4 extreme points

x^{8} (x - 7)^{4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-18ln(x) ?
The extreme f(x)=x^2-18ln(x) is Minimum(3,9-18ln(3))