What is the extreme f(x,y)=xy+pi/8 x^2 ?

The extreme f(x,y)=xy+pi/8 x^2 is Saddle(0,0)

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extreme f(x,y)=xy+pi/8 x^2

extreme points

f (x, y) = x y + \frac{π}{8} x^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = - 4 + x - x^{2}

k, p = c \cdot e^{k \cdot h}

x^{8} (x - 7)^{4}

f (x) = 12 x^{2} - 48 x + 20 [0.3]

f (x) = \frac{3}{x - 4}

What is the extreme f(x,y)=xy+pi/8 x^2 ?
The extreme f(x,y)=xy+pi/8 x^2 is Saddle(0,0)