What is the extreme f(x,y)=x^2+y^2+2x+2y ?

The extreme f(x,y)=x^2+y^2+2x+2y is Minimum(-1,-1)

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extreme f(x,y)=x^2+y^2+2x+2y

extreme points

f (x, y) = x^{2} + y^{2} + 2 x + 2 y

Minimum (- 1, - 1)

Solution steps

Find the critical points:

(- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(- 1, - 1) :

Minimum

Minimum (- 1, - 1)

7 x - 0.005 x^{2} - 3.6 x - 70

+ x^{2} - 2 x - 8

f (x) = 7 x y - λ (6 x + 11 y - 2)

\frac{x + 3}{x ^{2} - 4 x - 21}

What is the extreme f(x,y)=x^2+y^2+2x+2y ?
The extreme f(x,y)=x^2+y^2+2x+2y is Minimum(-1,-1)