What is the extreme+(x+1/x+8)/(x+1/x+2) ?

The extreme+(x+1/x+8)/(x+1/x+2) is Maximum(1, 5/2)

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extreme+(x+1/x+8)/(x+1/x+2)

extreme points

+ \frac{x + \frac{1}{x} + 8}{x + \frac{1}{x} + 2}

Maximum (1, \frac{5}{2})

Solution steps

f^{'} (x) = - \frac{6 ( x - 1 )}{( x + 1 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

+ \frac{x + \frac{1}{x} + 8}{x + \frac{1}{x} + 2} : \frac{5}{2}

Maximum (1, \frac{5}{2})

f (x, y) = 6 (1 - x^{(2)}) \cdot (1 - y^{(2)})

f (x) = - 2 x^{2} ln (x) + 17 x^{2}

∣ x + 4 ∣

f (x) = \frac{2 x ^{2} + 3}{x ^{2} - 1}

f (x) = 4 x + 8 cos (x)

What is the extreme+(x+1/x+8)/(x+1/x+2) ?
The extreme+(x+1/x+8)/(x+1/x+2) is Maximum(1, 5/2)