What is the extreme 2x^3-9x^2+12x-8 ?

The extreme 2x^3-9x^2+12x-8 is Maximum(1,-3),Minimum(2,-4)

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extreme 2x^3-9x^2+12x-8

extreme points

2 x^{3} - 9 x^{2} + 12 x - 8

Maximum (1, - 3), Minimum (2, - 4)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x + 12

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 1

into

2 x^{3} - 9 x^{2} + 12 x - 8 : - 3

Maximum (1, - 3)

Plug

x = 2

into

2 x^{3} - 9 x^{2} + 12 x - 8 : - 4

Minimum (2, - 4)

Maximum (1, - 3), Minimum (2, - 4)

f (x) = 4 x^{2} - x y + 2 y^{2}

f (x) = \frac{- 3 x + y - 4}{4 x ^{2} - 3 y + 2}

f (x) = 2 x + 5 x^{- 1}

a - \frac{ab}{( a + b )}

f (x) = (x - 2) (x - 3)^{\frac{1}{2}}

What is the extreme 2x^3-9x^2+12x-8 ?
The extreme 2x^3-9x^2+12x-8 is Maximum(1,-3),Minimum(2,-4)