What is the extreme f(x)=-5/4 x^2+5/2 x+7/4 ?

The extreme f(x)=-5/4 x^2+5/2 x+7/4 is Maximum(1,3)

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extreme f(x)=-5/4 x^2+5/2 x+7/4

extreme points

f (x) = - \frac{5}{4} x^{2} + \frac{5}{2} x + \frac{7}{4}

Maximum (1, 3)

Solution steps

f^{'} (x) = \frac{- 5 x + 5}{2}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

- \frac{5}{4} x^{2} + \frac{5}{2} x + \frac{7}{4} : 3

Maximum (1, 3)

f (x, y) = x + y - \frac{3}{2} (x^{2} + y^{2} + 1)

f (x) = e^{2 x} + e^{(- x)}

- x^{2} + 8 x - 9

f (x) = x^{3} - 12 x^{2} - 27 x + 2, 1 \leq x \leq 10

85 y^{35}

What is the extreme f(x)=-5/4 x^2+5/2 x+7/4 ?
The extreme f(x)=-5/4 x^2+5/2 x+7/4 is Maximum(1,3)