What is the extreme-0.015x^2+1.24x-7.4 ?

The extreme-0.015x^2+1.24x-7.4 is Maximum(124/3 ,18.22666…)

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extreme-0.015x^2+1.24x-7.4

extreme points

- 0.015 x^{2} + 1.24 x - 7.4

Maximum (\frac{124}{3}, 18.22666 \dots)

Solution steps

f^{'} (x) = - 0.03 x + 1.24

Find intervals:

Increasing

: - \infty < x < \frac{124}{3},

Decreasing

: \frac{124}{3} < x < \infty

Plug

x = \frac{124}{3}

into

- 0.015 x^{2} + 1.24 x - 7.4 : 18.22666 \dots

Maximum (\frac{124}{3}, 18.22666 \dots)

f (x, y) = - 3 y^{2} + 18 y - x^{2}

f (x, y) = y ln (2 x + y)

f (x, y) = 5 x^{2} + 5 x - 2 y + 4 y^{2}

f (x, y) = x^{2} + y^{2} - 10 x + 16 y - 6

f (x) = e^{- \frac{( x - 3 ) ^{2}}{2}} (- x + 3)

What is the extreme-0.015x^2+1.24x-7.4 ?
The extreme-0.015x^2+1.24x-7.4 is Maximum(124/3 ,18.22666…)