What is the extreme 2x^3-3x^2-12x+13 ?

The extreme 2x^3-3x^2-12x+13 is Maximum(-1,20),Minimum(2,-7)

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extreme 2x^3-3x^2-12x+13

extreme points

2 x^{3} - 3 x^{2} - 12 x + 13

Maximum (- 1, 20), Minimum (2, - 7)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x + 13 : 20

Maximum (- 1, 20)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x + 13 : - 7

Minimum (2, - 7)

Maximum (- 1, 20), Minimum (2, - 7)

y = - 11 sin (22 x + 33) + 44

f (t) = 2 e^{l n (x)} (t)

f (x) = \frac{2 ( x + 6 ) ^{2}}{x + 8}

f (x) = \frac{x ^{3} + x - 2}{x ^{2} - 4 x + 3}

\frac{5 x - 15}{2 x - 9}

What is the extreme 2x^3-3x^2-12x+13 ?
The extreme 2x^3-3x^2-12x+13 is Maximum(-1,20),Minimum(2,-7)