What is the extreme f(x)=2x^3-21x^2+72x-8 ?

The extreme f(x)=2x^3-21x^2+72x-8 is Maximum(3,73),Minimum(4,72)

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extreme f(x)=2x^3-21x^2+72x-8

extreme points

f (x) = 2 x^{3} - 21 x^{2} + 72 x - 8

Maximum (3, 73), Minimum (4, 72)

Solution steps

f^{'} (x) = 6 x^{2} - 42 x + 72

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 3

into

2 x^{3} - 21 x^{2} + 72 x - 8 : 73

Maximum (3, 73)

Plug

x = 4

into

2 x^{3} - 21 x^{2} + 72 x - 8 : 72

Minimum (4, 72)

Maximum (3, 73), Minimum (4, 72)

\frac{1}{x ^{2} + x + 1}

f (x) = e^{14 x} + e^{- x}

f (x) = x^{3} - 9 x^{2} - 21 x + 7

f (x) = x^{3} - 9 x^{2} - 21 x + 9

f (x) = 4 x^{2} - x - 5

What is the extreme f(x)=2x^3-21x^2+72x-8 ?
The extreme f(x)=2x^3-21x^2+72x-8 is Maximum(3,73),Minimum(4,72)