What is the extreme f(x,y)=x^2+xy+2x+5y-1 ?

The extreme f(x,y)=x^2+xy+2x+5y-1 is Saddle(-5,8)

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extreme f(x,y)=x^2+xy+2x+5y-1

extreme points

f (x, y) = x^{2} + x y + 2 x + 5 y - 1

Saddle (- 5, 8)

Solution steps

Find the critical points:

(- 5, 8)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(- 5, 8) :

Saddle

Saddle (- 5, 8)

0.01 x^{3} - 0.45 x^{2} + 2 x + 300

x e^{\frac{2}{x}}

50000 x + 40000 y - 10 x^{2} - 20 y^{2} - 10 x y

f (x) = \frac{1}{2} x^{2} - 9 x + 7

f (x) = - 3 x^{2} + 10 x - 3

What is the extreme f(x,y)=x^2+xy+2x+5y-1 ?
The extreme f(x,y)=x^2+xy+2x+5y-1 is Saddle(-5,8)