What is the extreme f(x)=3cos(x)+3sin(x) ?

The extreme f(x)=3cos(x)+3sin(x) is Maximum(pi/4+2pin,3sqrt(2)),Minimum((5pi)/4+2pin,-3sqrt(2))

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extreme f(x)=3cos(x)+3sin(x)

extreme points

f (x) = 3 cos (x) + 3 sin (x)

Maximum (\frac{π}{4} + 2 πn, 32), Minimum (\frac{5 π}{4} + 2 πn, - 32)

Solution steps

Find the critical points:

x = \frac{π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Domain of

3 cos (x) + 3 sin (x) : - \infty < x < \infty

Find intervals:

Increasing

: 2 πn \leq x < \frac{π}{4} + 2 πn,

Decreasing

: \frac{π}{4} + 2 πn < x < \frac{5 π}{4} + 2 πn,

Increasing

: \frac{5 π}{4} + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = \frac{π}{4} + 2 πn

into

3 cos (x) + 3 sin (x) \Rightarrow y = 32

Maximum (\frac{π}{4} + 2 πn, 32)

Plug the extreme point

x = \frac{5 π}{4} + 2 πn

into

3 cos (x) + 3 sin (x) \Rightarrow y = - 32

Minimum (\frac{5 π}{4} + 2 πn, - 32)

Maximum (\frac{π}{4} + 2 πn, 32), Minimum (\frac{5 π}{4} + 2 πn, - 32)

f (x) = \frac{x ^{2} + 4}{2 x}

f (x) = (5 - x) e^{x}

f (x, y) = y^{3} - y x^{2} - 3 y^{2} \cdot x^{2} + 3 x^{4}

2 x^{2} - 9 x - 1

f (x) = x + \frac{16}{x}, 4 \leq x \leq 25

What is the extreme f(x)=3cos(x)+3sin(x) ?
The extreme f(x)=3cos(x)+3sin(x) is Maximum(pi/4+2pin,3sqrt(2)),Minimum((5pi)/4+2pin,-3sqrt(2))