What is the extreme x+sqrt(4-x^2) ?

The extreme x+sqrt(4-x^2) is Minimum(-2,-2),Maximum(sqrt(2),2sqrt(2)),Minimum(2,2)

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extreme x+sqrt(4-x^2)

extreme points

x + 4 - x^{2}

Minimum (- 2, - 2), Maximum (2, 22), Minimum (2, 2)

Solution steps

f^{'} (x) = 1 - \frac{x}{4 - x ^{2}}

Find intervals:

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < 2

Plug

x = - 2

into

x + 4 - x^{2} : - 2

Minimum (- 2, - 2)

Plug

x = 2

into

x + 4 - x^{2} : 22

Maximum (2, 22)

Plug

x = 2

into

x + 4 - x^{2} : 2

Minimum (2, 2)

Minimum (- 2, - 2), Maximum (2, 22), Minimum (2, 2)

2000 - 10 x \cdot e^{5 \cdot (\frac{x ^{2}}{8})}

f (x) = 3 x^{2} - 3 y^{2} + 6 = 0

f (x) = 4 - x^{2}, - 2 \leq x \leq 2

f (x, y) = 2 x^{2} + y^{2} - 8 x + 8 y

f (x) = (x^{2} - 4)^{\frac{3}{4}}

What is the extreme x+sqrt(4-x^2) ?
The extreme x+sqrt(4-x^2) is Minimum(-2,-2),Maximum(sqrt(2),2sqrt(2)),Minimum(2,2)