What is the extreme f(x)=39+6x+(54)/x ?

The extreme f(x)=39+6x+(54)/x is Maximum(-3,3),Minimum(3,75)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=39+6x+(54)/x

extreme points

f (x) = 39 + 6 x + \frac{54}{x}

Maximum (- 3, 3), Minimum (3, 75)

Solution steps

f^{'} (x) = - \frac{54}{x ^{2}} + 6

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

39 + 6 x + \frac{54}{x} : 3

Maximum (- 3, 3)

Plug

x = 3

into

39 + 6 x + \frac{54}{x} : 75

Minimum (3, 75)

Maximum (- 3, 3), Minimum (3, 75)

\frac{e ^{x}}{x ^{4}}

F (x, y) = x^{2} + x y + y^{2} + 3 x - 3 y + 4

f (x, y) = 6 - 2 x + 4 y - x^{2} - 4 y^{2}

f (x) = (4 x - 1)^{2}

f (x) = 5 x^{2} - 10 x + 2, - 4 \leq x \leq 2

What is the extreme f(x)=39+6x+(54)/x ?
The extreme f(x)=39+6x+(54)/x is Maximum(-3,3),Minimum(3,75)