What is the extreme xsqrt(x+7) ?

The extreme xsqrt(x+7) is Maximum(-7,0),Minimum(-14/3 ,-(14sqrt(7))/(3sqrt(3)))

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extreme xsqrt(x+7)

extreme points

x x + 7

Maximum (- 7, 0), Minimum (- \frac{14}{3}, - \frac{14 7}{3 3})

Solution steps

f^{'} (x) = \frac{3 x + 14}{2 x + 7}

Find intervals:

Decreasing

: - 7 < x < - \frac{14}{3},

Increasing

: - \frac{14}{3} < x < \infty

Plug

x = - 7

into

x x + 7 : 0

Maximum (- 7, 0)

Plug

x = - \frac{14}{3}

into

x x + 7 : - \frac{14 7}{3 3}

Minimum (- \frac{14}{3}, - \frac{14 7}{3 3})

Maximum (- 7, 0), Minimum (- \frac{14}{3}, - \frac{14 7}{3 3})

f (y) = x y

f (x) = - x^{2} + 120 x - 3200

2 x^{3} - 3 x^{2} - 36 x + 54

2 x^{2} - x y + y^{2} + 7 x

f (x, y) = x^{3} + 2 x y^{2} + \frac{y ^{4}}{x}

What is the extreme xsqrt(x+7) ?
The extreme xsqrt(x+7) is Maximum(-7,0),Minimum(-14/3 ,-(14sqrt(7))/(3sqrt(3)))