What is the extreme ((x-2)(3-x))/(x^2) ?

The extreme ((x-2)(3-x))/(x^2) is Maximum(12/5 , 1/24)

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extreme ((x-2)(3-x))/(x^2)

extreme points

\frac{( x - 2 ) ( 3 - x )}{x ^{2}}

Maximum (\frac{12}{5}, \frac{1}{24})

Solution steps

f^{'} (x) = \frac{- 5 x + 12}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{12}{5},

Decreasing

: \frac{12}{5} < x < \infty

Plug

x = \frac{12}{5}

into

\frac{( x - 2 ) ( 3 - x )}{x ^{2}} : \frac{1}{24}

Maximum (\frac{12}{5}, \frac{1}{24})

- x^{(2)} - 9

f (x, y) = e^{l n (x^{2} + y^{2})}

f (x) = - 20 x^{2} + 1960 x

f (x) = (3 - x) e^{- x}

2 x^{3} - 3 x^{2} - 36 x + 19

What is the extreme ((x-2)(3-x))/(x^2) ?
The extreme ((x-2)(3-x))/(x^2) is Maximum(12/5 , 1/24)