en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=(5x)/(x^2-1)

Solution

extreme points

y = \frac{5 x}{x ^{2} - 1}

Solution

None

Solution steps

f^{'} (x) = \frac{5 ( - x ^{2} - 1 )}{( x ^{2} - 1 ) ^{2}}

Find intervals:

None

None

Popular Examples

extreme x^2-9x+5 extreme points

x^{2} - 9 x + 5

extreme f(x)=x(x+1)^2(x-3)extreme points

f (x) = x (x + 1)^{2} (x - 3)

extreme f(x)=12y-64 extreme points

f (x) = 12 y - 64

extreme f(x)=y-e-2x^2y extreme points

f (x) = y - e - 2 x^{2} y

extreme f(x)=(x^2-16)^{1/9},-5<= x<= 4 extreme points

f (x) = (x^{2} - 16)^{\frac{1}{9}}, - 5 \leq x \leq 4

Frequently Asked Questions (FAQ)

What is the extreme y=(5x)/(x^2-1) ?
The extreme y=(5x)/(x^2-1) is None