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Popular >

extreme f(x)=2x^2-2x

Solution

extreme points

f (x) = 2 x^{2} - 2 x

Solution

Minimum (\frac{1}{2}, - \frac{1}{2})

Solution steps

f^{'} (x) = 4 x - 2

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{2} - 2 x : - \frac{1}{2}

Minimum (\frac{1}{2}, - \frac{1}{2})

Popular Examples

extreme f(x)=-x^3-10x extreme points

f (x) = - x^{3} - 10 x

extreme f(x,y)=6x^2-5y^2+6x+y+5 extreme points

f (x, y) = 6 x^{2} - 5 y^{2} + 6 x + y + 5

extreme f(x)=ln((x+3)/(x-3))extreme points

f (x) = ln (\frac{x + 3}{x - 3})

extreme f(x)=-(15x^4)/4-(5x^3)/3-4 extreme points

f (x) = - \frac{15 x ^{4}}{4} - \frac{5 x ^{3}}{3} - 4

extreme f(x)=((x^2-11x+82))/(x-9)extreme points

f (x) = \frac{( x ^{2} - 11 x + 82 )}{x - 9}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-2x ?
The extreme f(x)=2x^2-2x is Minimum(1/2 ,-1/2)