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Popular >

extreme f(x)=5x^2-4x+4

Solution

extreme points

f (x) = 5 x^{2} - 4 x + 4

Solution

Minimum (\frac{2}{5}, \frac{16}{5})

Solution steps

f^{'} (x) = 10 x - 4

Find intervals:

Decreasing

: - \infty < x < \frac{2}{5},

Increasing

: \frac{2}{5} < x < \infty

Plug

x = \frac{2}{5}

into

5 x^{2} - 4 x + 4 : \frac{16}{5}

Minimum (\frac{2}{5}, \frac{16}{5})

Popular Examples

extreme f(x)=-2x^2-3x+1 extreme points

f (x) = - 2 x^{2} - 3 x + 1

extreme f(x)=-2x^2-3x+4 extreme points

f (x) = - 2 x^{2} - 3 x + 4

extreme 1/(x^3-2x)extreme points

\frac{1}{x ^{3} - 2 x}

extreme f(x,y)=4y^3x^2-12y^2-36y+2 extreme points

f (x, y) = 4 y^{3} x^{2} - 12 y^{2} - 36 y + 2

extreme f(x)=4x^2+5x-2 extreme points

f (x) = 4 x^{2} + 5 x - 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=5x^2-4x+4 ?
The extreme f(x)=5x^2-4x+4 is Minimum(2/5 , 16/5)