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Popular >

extreme f(x)=4x^2+5x-2

Solution

extreme points

f (x) = 4 x^{2} + 5 x - 2

Solution

Minimum (- \frac{5}{8}, - \frac{57}{16})

Solution steps

f^{'} (x) = 8 x + 5

Find intervals:

Decreasing

: - \infty < x < - \frac{5}{8},

Increasing

: - \frac{5}{8} < x < \infty

Plug

x = - \frac{5}{8}

into

4 x^{2} + 5 x - 2 : - \frac{57}{16}

Minimum (- \frac{5}{8}, - \frac{57}{16})

Popular Examples

extreme f(x)=x^5+3x^4-2x+1 extreme points

f (x) = x^{5} + 3 x^{4} - 2 x + 1

extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 extreme points

f (x) = - 2 x^{3} + 39 x^{2} - 240, 4 \leq x \leq 9

extreme f(x)=3x^2e^{-2x}+1 extreme points

f (x) = 3 x^{2} e^{- 2 x} + 1

extreme f(x)=8(x^2)/((x-6)),-3<= x<= 2 extreme points

f (x) = 8 \frac{x ^{2}}{( x - 6 )}, - 3 \leq x \leq 2

extreme f(x)=-0.05x^2+300x+2000 extreme points

f (x) = - 0.05 x^{2} + 300 x + 2000

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2+5x-2 ?
The extreme f(x)=4x^2+5x-2 is Minimum(-5/8 ,-57/16)