What is the extreme f(x)=2+4x+100x^{-1} ?

The extreme f(x)=2+4x+100x^{-1} is Maximum(-5,-38),Minimum(5,42)

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extreme f(x)=2+4x+100x^{-1}

extreme points

f (x) = 2 + 4 x + 100 x^{- 1}

Maximum (- 5, - 38), Minimum (5, 42)

Solution steps

f^{'} (x) = - \frac{100}{x ^{2}} + 4

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

2 + 4 x + 100 x^{- 1} : - 38

Maximum (- 5, - 38)

Plug

x = 5

into

2 + 4 x + 100 x^{- 1} : 42

Minimum (5, 42)

Maximum (- 5, - 38), Minimum (5, 42)

f (x, y) = x^{2} + y^{2} - 12 x + 16 y

x^{\frac{1}{7}} + 1

f (x) = x^{3} + 6 x^{2} - 6 [- 8.3]

f (x) = \frac{8 ( x ^{2} - 1 )}{3 x ^{\frac{1}{3}}}

f (x) = x 13 - x^{2}

What is the extreme f(x)=2+4x+100x^{-1} ?
The extreme f(x)=2+4x+100x^{-1} is Maximum(-5,-38),Minimum(5,42)