What is the extreme f(xy)=8x^3+20x^2y+40y^3 ?

The extreme f(xy)=8x^3+20x^2y+40y^3 is None

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extreme f(xy)=8x^3+20x^2y+40y^3

extreme points

f (x y) = 8 x^{3} + 20 x^{2} y + 40 y^{3}

None

Solution steps

Find the critical points:

None

8 x^{3} + 20 x^{2} y + 40 y^{3}

has no critical points, therefore there are no extreme points

None

f (x) = - 6 x - \frac{864}{x}

f (x) = 4 x^{3} + 9 x^{2} - 12 x + 10

f (x) = x^{2} + y^{2} + 8 x - 2 y + 8

- 2 x^{2} - 900

y, f = - \frac{40000 x}{( 3 + x ^{2} + 2 y ^{2} ) ^{2}}

What is the extreme f(xy)=8x^3+20x^2y+40y^3 ?
The extreme f(xy)=8x^3+20x^2y+40y^3 is None