What is the extreme f(x)=x^4e^{-7x} ?

The extreme f(x)=x^4e^{-7x} is Minimum(0,0),Maximum(4/7 ,(256)/(2401e^4))

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extreme f(x)=x^4e^{-7x}

extreme points

f (x) = x^{4} e^{- 7 x}

Minimum (0, 0), Maximum (\frac{4}{7}, \frac{256}{2401 e ^{4}})

Solution steps

f^{'} (x) = e^{- 7 x} x^{3} (4 - 7 x)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{4}{7},

Decreasing

: \frac{4}{7} < x < \infty

Plug

x = 0

into

x^{4} e^{- 7 x} : 0

Minimum (0, 0)

Plug

x = \frac{4}{7}

into

x^{4} e^{- 7 x} : \frac{256}{2401 e ^{4}}

Maximum (\frac{4}{7}, \frac{256}{2401 e ^{4}})

Minimum (0, 0), Maximum (\frac{4}{7}, \frac{256}{2401 e ^{4}})

y = 8 + \frac{2}{x}

f (x) = 49 - x^{2}, (- 7, 7)

147 - p^{2}

40 x^{3} + 9 x^{2} - 12 x - 8

What is the extreme f(x)=x^4e^{-7x} ?
The extreme f(x)=x^4e^{-7x} is Minimum(0,0),Maximum(4/7 ,(256)/(2401e^4))