What is the extreme f(x)=-x^3-9x^2-27x-8 ?

The extreme f(x)=-x^3-9x^2-27x-8 is Saddle(-3,19)

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extreme f(x)=-x^3-9x^2-27x-8

extreme points

f (x) = - x^{3} - 9 x^{2} - 27 x - 8

Saddle (- 3, 19)

Solution steps

f^{'} (x) = - 3 x^{2} - 18 x - 27

Find intervals:

Decreasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < \infty

Plug

x = - 3

into

- x^{3} - 9 x^{2} - 27 x - 8 : 19

Saddle (- 3, 19)

- cos (3 (θ - \frac{π}{6}))

f (x) = x^{2} - 10 x

f (x) = 2 x^{3} + 12 x^{2} + 16 x

\frac{x ^{2}}{x ^{2} + 16}

9 - 2 x^{2}

What is the extreme f(x)=-x^3-9x^2-27x-8 ?
The extreme f(x)=-x^3-9x^2-27x-8 is Saddle(-3,19)