What is the extreme f(x)=x^3-2x^2+3,(2,7) ?

The extreme f(x)=x^3-2x^2+3,(2,7) is None

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extreme f(x)=x^3-2x^2+3,(2,7)

extreme points

f (x) = x^{3} - 2 x^{2} + 3, (2, 7)

None

Solution steps

Find the critical points:

None

x^{3} - 2 x^{2} + 3

has no critical points, therefore there are no extreme points

None

2 cos (x) - 2

f (x) = x^{2} (x + 3)^{4}

f (y) = 6 - 3 x - 2 y

y^{2} - 120 y

f (x) = 4 - 3 x^{3}

What is the extreme f(x)=x^3-2x^2+3,(2,7) ?
The extreme f(x)=x^3-2x^2+3,(2,7) is None