What is the extreme f(x)=3x^4-x^2+4x-2 ?

The extreme f(x)=3x^4-x^2+4x-2 is Minimum(-0.77317…,-4.61840…)

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extreme f(x)=3x^4-x^2+4x-2

extreme points

f (x) = 3 x^{4} - x^{2} + 4 x - 2

Minimum (- 0.77317 \dots, - 4.61840 \dots)

Solution steps

Find the critical points:

x \approx - 0.77317 \dots

Domain of

3 x^{4} - x^{2} + 4 x - 2 : - \infty < x < \infty

Find intervals:

Decreasing

: - \infty < x < - 0.77317 \dots,

Increasing

: - 0.77317 \dots < x < \infty

Plug the extreme point

x = - 0.77317 \dots

into

3 x^{4} - x^{2} + 4 x - 2 \Rightarrow y = - 4.61840 \dots

Minimum (- 0.77317 \dots, - 4.61840 \dots)

f (x) = x^{4} + 8 x^{3} + 3

f (x, y) = 3 x + 4 y + 1

f (x) = 2 x^{4} + 2 y^{4} - x y

f (4.6) = x^{y}

E (X, Y) = (X + Y)^{2} - 3 (X + Y) (X - Y)

What is the extreme f(x)=3x^4-x^2+4x-2 ?
The extreme f(x)=3x^4-x^2+4x-2 is Minimum(-0.77317…,-4.61840…)