What is the extreme f(x)=2x^5-x^4-9x^3+13x^2-5x ?

The extreme f(x)=2x^5-x^4-9x^3+13x^2-5x is

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extreme f(x)=2x^5-x^4-9x^3+13x^2-5x

extreme points

f (x) = 2 x^{5} - x^{4} - 9 x^{3} + 13 x^{2} - 5 x

Maximum (- \frac{8 + 114}{10}, \frac{3 ( 114831 + 10982 114 )}{12500}), Minimum (\frac{- 8 + 114}{10}, \frac{3 ( 114831 - 10982 114 )}{12500}), Saddle (1, 0)

Solution steps

f^{'} (x) = 10 x^{4} - 4 x^{3} - 27 x^{2} + 26 x - 5

Find intervals:

Increasing

: - \infty < x < - \frac{8 + 114}{10},

Decreasing

: - \frac{8 + 114}{10} < x < \frac{114 - 8}{10},

Increasing

: \frac{114 - 8}{10} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{8 + 114}{10}

into

2 x^{5} - x^{4} - 9 x^{3} + 13 x^{2} - 5 x : \frac{3 ( 114831 + 10982 114 )}{12500}

Maximum (- \frac{8 + 114}{10}, \frac{3 ( 114831 + 10982 114 )}{12500})

Plug

x = \frac{- 8 + 114}{10}

into

2 x^{5} - x^{4} - 9 x^{3} + 13 x^{2} - 5 x : \frac{3 ( 114831 - 10982 114 )}{12500}

Minimum (\frac{- 8 + 114}{10}, \frac{3 ( 114831 - 10982 114 )}{12500})

Plug

x = 1

into

2 x^{5} - x^{4} - 9 x^{3} + 13 x^{2} - 5 x : 0

Saddle (1, 0)

Maximum (- \frac{8 + 114}{10}, \frac{3 ( 114831 + 10982 114 )}{12500}), Minimum (\frac{- 8 + 114}{10}, \frac{3 ( 114831 - 10982 114 )}{12500}), Saddle (1, 0)

y = \frac{( x + 1 )}{x ^{2} + 4 x - 5}

f (x) = x (x + 4), x \geq 0

f (x) = 190 + 8 x^{3} + x^{4}

y = 4 - 6 x + x^{2}

What is the extreme f(x)=2x^5-x^4-9x^3+13x^2-5x ?
The extreme f(x)=2x^5-x^4-9x^3+13x^2-5x is