What is the extreme f(x)=0.002x^2+3.4x-20 ?

The extreme f(x)=0.002x^2+3.4x-20 is Minimum(-850,-1465)

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extreme f(x)=0.002x^2+3.4x-20

extreme points

f (x) = 0.002 x^{2} + 3.4 x - 20

Minimum (- 850, - 1465)

Solution steps

f^{'} (x) = 0.004 x + 3.4

Find intervals:

Decreasing

: - \infty < x < - 850,

Increasing

: - 850 < x < \infty

Plug

x = - 850

into

0.002 x^{2} + 3.4 x - 20 : - 1465

Minimum (- 850, - 1465)

f (x, y) = x^{3} + 2 y^{2} - 27 x - 8 y - 4

f (x) = x^{\frac{1}{3}} + 9

f (x) = (x^{2} + y^{2})^{2} = 2 \cdot (x^{2} - y^{2})

x^{3} + 3 x y^{2} - 3 x

f (x) = x^{\frac{2}{3}} (x - 2), - 2 \leq x \leq 2

What is the extreme f(x)=0.002x^2+3.4x-20 ?
The extreme f(x)=0.002x^2+3.4x-20 is Minimum(-850,-1465)