What is the domain of 1/(2x^2-x-6) ?

The domain of 1/(2x^2-x-6) is x 2

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domain of 1/(2x^2-x-6)

domain

\frac{1}{2 x ^{2} - x - 6}

x < - \frac{3}{2} or - \frac{3}{2} < x < 2 or x > 2

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or - \frac{3}{2} < x < 2 or x > 2

9 - (x - 4)^{2}

f (x) = \frac{3 x ^{2} + 12 x}{x ^{2} + 5 x + 4}

f (x) = \frac{4}{x ^{2} - 3 x}

y = \frac{( x + 2 )}{3}

f (x) = \frac{1}{4}

What is the domain of 1/(2x^2-x-6) ?
The domain of 1/(2x^2-x-6) is x<-3/2 \lor-3/2 <x<2\lor x>2