What is the extreme y=0.0004x^2-0.0118x+2.6821 ?

The extreme y=0.0004x^2-0.0118x+2.6821 is Minimum((0.0118)/(0.0008),2.595075)

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extreme y=0.0004x^2-0.0118x+2.6821

extreme points

y = 0.0004 x^{2} - 0.0118 x + 2.6821

Minimum (\frac{0.0118}{0.0008}, 2.595075)

Solution steps

f^{'} (x) = 0.0008 x - 0.0118

Find intervals:

Decreasing

: - \infty < x < \frac{0.0118}{0.0008},

Increasing

: \frac{0.0118}{0.0008} < x < \infty

Plug

x = \frac{0.0118}{0.0008}

into

0.0004 x^{2} - 0.0118 x + 2.6821 : 2.595075

Minimum (\frac{0.0118}{0.0008}, 2.595075)

x (\frac{8}{5} x^{3} - 2 x^{2})

f (x) = ln (\frac{4 - x}{2 + 2 x})

f (x) = x^{(2)} - 5 x + 4

f (y) = - 0.06 x^{2} - 0.02 y^{2} - 1.5 x y - 85 x + 69 y

f (x) = 3 x + 5

What is the extreme y=0.0004x^2-0.0118x+2.6821 ?
The extreme y=0.0004x^2-0.0118x+2.6821 is Minimum((0.0118)/(0.0008),2.595075)