What is the extreme y=-4x^3-6x^2+360x-12 ?

The extreme y=-4x^3-6x^2+360x-12 is Minimum(-6,-1524),Maximum(5,1138)

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extreme y=-4x^3-6x^2+360x-12

extreme points

y = - 4 x^{3} - 6 x^{2} + 360 x - 12

Minimum (- 6, - 1524), Maximum (5, 1138)

Solution steps

f^{'} (x) = - 12 x^{2} - 12 x + 360

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - 6

into

- 4 x^{3} - 6 x^{2} + 360 x - 12 : - 1524

Minimum (- 6, - 1524)

Plug

x = 5

into

- 4 x^{3} - 6 x^{2} + 360 x - 12 : 1138

Maximum (5, 1138)

Minimum (- 6, - 1524), Maximum (5, 1138)

f (x) = 2 x^{4} + x^{3} - 13 x^{2} - 9 x - 45

f (x) = \frac{2 x ^{2} - 5 x}{2 x + 7}

f (x) = 4 x e^{- 3 x}

f (x) = y (3 x - 5)

f (x) = 3 x - 7

What is the extreme y=-4x^3-6x^2+360x-12 ?
The extreme y=-4x^3-6x^2+360x-12 is Minimum(-6,-1524),Maximum(5,1138)