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Popular >

extreme f(x)=-12x^2+100

Solution

extreme points

f (x) = - 12 x^{2} + 100

Solution

Maximum (0, 100)

Solution steps

f^{'} (x) = - 24 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- 12 x^{2} + 100 : 100

Maximum (0, 100)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-12x^2+100 ?
The extreme f(x)=-12x^2+100 is Maximum(0,100)