What is the extreme 13x^2-273x+10840 ?

The extreme 13x^2-273x+10840 is Minimum(21/2 , 37627/4)

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extreme 13x^2-273x+10840

extreme points

13 x^{2} - 273 x + 10840

Minimum (\frac{21}{2}, \frac{37627}{4})

Solution steps

f^{'} (x) = 26 x - 273

Find intervals:

Decreasing

: - \infty < x < \frac{21}{2},

Increasing

: \frac{21}{2} < x < \infty

Plug

x = \frac{21}{2}

into

13 x^{2} - 273 x + 10840 : \frac{37627}{4}

Minimum (\frac{21}{2}, \frac{37627}{4})

2 cos (\frac{2 π t}{3})

x^{3} - 12 x + 16

x^{3} - 12 x + 12

f (x, y) = x^{2} + 5 x y + y^{2} - 2 x + 4 y + 5

f (x, y) = 9 x y + \frac{1000}{y} + \frac{1000}{x}

What is the extreme 13x^2-273x+10840 ?
The extreme 13x^2-273x+10840 is Minimum(21/2 , 37627/4)