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Popular >

extreme p(x)=9x^4+9x^2-18

Solution

extreme points

p (x) = 9 x^{4} + 9 x^{2} - 18

Solution

Minimum (0, - 18)

Solution steps

f^{'} (x) = 36 x^{3} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

9 x^{4} + 9 x^{2} - 18 : - 18

Minimum (0, - 18)

Popular Examples

extreme f(x)=2x^3+6x^2-48x+6[4.6]extreme points

f (x) = 2 x^{3} + 6 x^{2} - 48 x + 6 [4.6]

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f (x) = 3 sin (x), - π \leq x \leq 2 π

extreme f(x,y)=x^2+10xy+y^2 extreme points

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extreme f(x)=x^3-9/2 x^2-54x+12 extreme points

f (x) = x^{3} - \frac{9}{2} x^{2} - 54 x + 12

extreme f(x)=x^2-6x^2+1 extreme points

f (x) = x^{2} - 6 x^{2} + 1

Frequently Asked Questions (FAQ)

What is the extreme p(x)=9x^4+9x^2-18 ?
The extreme p(x)=9x^4+9x^2-18 is Minimum(0,-18)