What is the extreme f(x)=18500(0.25-r^2) ?

The extreme f(x)=18500(0.25-r^2) is Maximum(0,4625)

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extreme f(x)=18500(0.25-r^2)

extreme points

f (x) = 18500 (0.25 - r^{2})

Maximum (0, 4625)

Solution steps

f^{'} (r) = - 37000 r

Find intervals:

Increasing

: - \infty < r < 0,

Decreasing

: 0 < r < \infty

Plug

r = 0

into

18500 (0.25 - r^{2}) : 4625

Maximum (0, 4625)

f (x) = - x^{2} + 8 x - 15, 3 \leq x \leq 5

f (x) = - 2 x^{2} - 2 y^{2} + 20 x + 16 y - 4

f (x) = x^{3} + 3 x^{2} - 45 x

f (x) = \frac{4}{x - 2}, 2 < x \leq 6

f (x) = 3 x + 2 y + 7

What is the extreme f(x)=18500(0.25-r^2) ?
The extreme f(x)=18500(0.25-r^2) is Maximum(0,4625)