What is the extreme f(x)=2x^3-39x^2+180x+1 ?

The extreme f(x)=2x^3-39x^2+180x+1 is Maximum(3,244),Minimum(10,-99)

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extreme f(x)=2x^3-39x^2+180x+1

extreme points

f (x) = 2 x^{3} - 39 x^{2} + 180 x + 1

Maximum (3, 244), Minimum (10, - 99)

Solution steps

f^{'} (x) = 6 x^{2} - 78 x + 180

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = 3

into

2 x^{3} - 39 x^{2} + 180 x + 1 : 244

Maximum (3, 244)

Plug

x = 10

into

2 x^{3} - 39 x^{2} + 180 x + 1 : - 99

Minimum (10, - 99)

Maximum (3, 244), Minimum (10, - 99)

y = 6 x - 12

1353.0186700000000 \dots

f (x) = \frac{1}{8} (x + 4)^{2} (6 - x)

f (x) = ln (\frac{4 x ^{2}}{ln ( x )})

f (x) = - x^{3} + 3 x^{2} + 9 x - 27

What is the extreme f(x)=2x^3-39x^2+180x+1 ?
The extreme f(x)=2x^3-39x^2+180x+1 is Maximum(3,244),Minimum(10,-99)