What is the extreme y=x^4ln(x/(10)) ?

The extreme y=x^4ln(x/(10)) is Minimum((10}{\sqrt[4]{e}},-\frac{2500)/e)

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extreme y=x^4ln(x/(10))

extreme points

y = x^{4} ln (\frac{x}{10})

Solution steps

f^{'} (x) = 4 x^{3} ln (\frac{x}{10}) + x^{3}

Find intervals:

Decreasing

Increasing

Plug

into

x^{4} ln (\frac{x}{10}) : - \frac{2500}{e}

f (x) = \frac{18}{( x ^{2} - 9 )}

f (x) = x^{3} - x^{2} - x + 7, - 1 \leq x \leq 2

g (t) = 8 t - t^{4}

f (x, y) = - 4 x y (x + y) - 9

f (x, y) = ln (10 - x^{2} - y^{2})

What is the extreme y=x^4ln(x/(10)) ?
The extreme y=x^4ln(x/(10)) is Minimum((10}{\sqrt[4]{e}},-\frac{2500)/e)