What is the extreme f(x)=-2x^3+33x^2-168x+10 ?

The extreme f(x)=-2x^3+33x^2-168x+10 is Minimum(4,-262),Maximum(7,-235)

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extreme f(x)=-2x^3+33x^2-168x+10

extreme points

f (x) = - 2 x^{3} + 33 x^{2} - 168 x + 10

Minimum (4, - 262), Maximum (7, - 235)

Solution steps

f^{'} (x) = - 6 x^{2} + 66 x - 168

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < 7,

Decreasing

: 7 < x < \infty

Plug

x = 4

into

- 2 x^{3} + 33 x^{2} - 168 x + 10 : - 262

Minimum (4, - 262)

Plug

x = 7

into

- 2 x^{3} + 33 x^{2} - 168 x + 10 : - 235

Maximum (7, - 235)

Minimum (4, - 262), Maximum (7, - 235)

f (x) = 4 x^{3} - 6 x^{2} - 144 x + 1

f (x, y) = \frac{20480}{x} + \frac{20480}{y} + 5 x y

f (x) = 2 x^{3} + 6 x^{2} - 144 x + 2, - 6 \leq x \leq 5

f (x) = \frac{x ^{3}}{3} + x

f (x) = (9 sin (x) - 9) (2 cos (x) 3)

What is the extreme f(x)=-2x^3+33x^2-168x+10 ?
The extreme f(x)=-2x^3+33x^2-168x+10 is Minimum(4,-262),Maximum(7,-235)