extreme f(x)=3^{2/3}-2x(-1.1)

解答

极值点

f (x) = 3^{\frac{2}{3}} - 2 x (- 1.1)

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求解步骤

f^{'} (x) = 2.2

Find intervals:

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e x t re m e f (x) = - 0.001 x^{2} + 6 x - 1900

e x t re m e h (x) = 5 (x - 1)^{\frac{2}{3}}, 0 \leq x \leq 2

e x t re m e f (x) = - 4 x^{3} + 6 x^{2} + 6

e x t re m e f (x, y) = \frac{5}{2} x^{2} + x y^{2} + 5 y^{2}

e x t re m e f (x) = (3 6 x^{2} - x^{3})