What is the extreme f(x)=2x^3-33x^2+168x+7 ?

The extreme f(x)=2x^3-33x^2+168x+7 is Maximum(4,279),Minimum(7,252)

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extreme f(x)=2x^3-33x^2+168x+7

extreme points

f (x) = 2 x^{3} - 33 x^{2} + 168 x + 7

Maximum (4, 279), Minimum (7, 252)

Solution steps

f^{'} (x) = 6 x^{2} - 66 x + 168

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = 4

into

2 x^{3} - 33 x^{2} + 168 x + 7 : 279

Maximum (4, 279)

Plug

x = 7

into

2 x^{3} - 33 x^{2} + 168 x + 7 : 252

Minimum (7, 252)

Maximum (4, 279), Minimum (7, 252)

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What is the extreme f(x)=2x^3-33x^2+168x+7 ?
The extreme f(x)=2x^3-33x^2+168x+7 is Maximum(4,279),Minimum(7,252)