What is the extreme f(x)=x[18-2(x)]^2 ?

The extreme f(x)=x[18-2(x)]^2 is Maximum(3,432),Minimum(9,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x[18-2(x)]^2

extreme points

f (x) = x [18 - 2 (x)]^{2}

Maximum (3, 432), Minimum (9, 0)

Solution steps

f^{'} (x) = 12 (x - 9) (x - 3)

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = 3

into

x [18 - 2 x]^{2} : 432

Maximum (3, 432)

Plug

x = 9

into

x [18 - 2 x]^{2} : 0

Minimum (9, 0)

Maximum (3, 432), Minimum (9, 0)

f (x, y) = x^{2} - 3 y^{2} - 8 x + 9 y + 3 x y

f (d, y) = \frac{d}{d ^{2}} (y)

y = - 5 cos (3 x) - 2

f (x, y) = 3 x^{\frac{1}{3}} y^{\frac{1}{3}}

f (x) = \frac{x ^{2}}{x - 1}

What is the extreme f(x)=x[18-2(x)]^2 ?
The extreme f(x)=x[18-2(x)]^2 is Maximum(3,432),Minimum(9,0)