What is the extreme f(x)=(2x-6)/(sqrt(x^2+7)-4) ?

The extreme f(x)=(2x-6)/(sqrt(x^2+7)-4) is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(2x-6)/(sqrt(x^2+7)-4)

extreme points

f (x) = \frac{2 x - 6}{x ^{2} + 7 - 4}

None

Solution steps

f^{'} (x) = \frac{6 x - 8 x ^{2} + 7 + 14}{( x ^{2} + 7 - 4 ) ^{2} x ^{2} + 7}

Find intervals:

None

None

f (x) = (5 + x) + (1000 + 100 x)

f (x) = - (\frac{x}{3})^{3} + 2 x^{2} + 12 x + 1

y = 5 + 6 x - 8 x^{3}

f (x) = \frac{2 x + 4}{x ^{2} + 4}

f (x) = (6 x + 1) e^{8 x - x^{2}}

What is the extreme f(x)=(2x-6)/(sqrt(x^2+7)-4) ?
The extreme f(x)=(2x-6)/(sqrt(x^2+7)-4) is None