What is the extreme f(x)=(x+5)/(x-3),(-5,2) ?

The extreme f(x)=(x+5)/(x-3),(-5,2) is None

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extreme f(x)=(x+5)/(x-3),(-5,2)

extreme points

f (x) = \frac{x + 5}{x - 3}, (- 5, 2)

None

Solution steps

Find the critical points:

None

\frac{x + 5}{x - 3}

has no critical points, therefore there are no extreme points

None

f (x) = - \frac{1}{3} x^{3} - x^{2} - 12

f (x) = - \frac{24 x}{x ^{2} + 9}

- 2 x^{2} - 12 x - 17

f (x) = 5 x e^{- x}, 0 \leq x \leq 2

f (x) = 2 x^{3} - 9 x^{2} + 60 x + 8

What is the extreme f(x)=(x+5)/(x-3),(-5,2) ?
The extreme f(x)=(x+5)/(x-3),(-5,2) is None