What is the extreme f(x)=-x^3+3x^2+429x+5242 ?

The extreme f(x)=-x^3+3x^2+429x+5242 is Minimum(-11,2217),Maximum(13,9129)

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extreme f(x)=-x^3+3x^2+429x+5242

extreme points

f (x) = - x^{3} + 3 x^{2} + 429 x + 5242

Minimum (- 11, 2217), Maximum (13, 9129)

Solution steps

f^{'} (x) = - 3 x^{2} + 6 x + 429

Find intervals:

Decreasing

: - \infty < x < - 11,

Increasing

: - 11 < x < 13,

Decreasing

: 13 < x < \infty

Plug

x = - 11

into

- x^{3} + 3 x^{2} + 429 x + 5242 : 2217

Minimum (- 11, 2217)

Plug

x = 13

into

- x^{3} + 3 x^{2} + 429 x + 5242 : 9129

Maximum (13, 9129)

Minimum (- 11, 2217), Maximum (13, 9129)

f (t) = 108 t - t^{3}

f (x) = 2 x^{3} + 6 x^{2} - 90 x + 1, - 5 \leq x \leq 7

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 2 x + 1

\frac{1}{2 π} e^{- (x - 3)^{\frac{2}{2}}}

f (x) = 4 (e^{- 0.05 x} - e^{- 0.55 x})

What is the extreme f(x)=-x^3+3x^2+429x+5242 ?
The extreme f(x)=-x^3+3x^2+429x+5242 is Minimum(-11,2217),Maximum(13,9129)