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Popular >

extreme y=x^3+3x^2

Solution

extreme points

y = x^{3} + 3 x^{2}

Solution

Maximum (- 2, 4), Minimum (0, 0)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} : 4

Maximum (- 2, 4)

Plug

x = 0

into

x^{3} + 3 x^{2} : 0

Minimum (0, 0)

Maximum (- 2, 4), Minimum (0, 0)

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Frequently Asked Questions (FAQ)

What is the extreme y=x^3+3x^2 ?
The extreme y=x^3+3x^2 is Maximum(-2,4),Minimum(0,0)