en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=sqrt(x+12)-8

Solution

extreme points

f (x) = x + 12 - 8

Solution

Minimum (- 12, - 8)

Solution steps

f^{'} (x) = \frac{1}{2 x + 12}

Find intervals:

Increasing

: - 12 < x < \infty

Plug

x = - 12

into

x + 12 - 8 : - 8

Minimum (- 12, - 8)

Popular Examples

extreme f(x,y)=4xy+120y-20y^2-1/10 x^2y-90 extreme points

f (x, y) = 4 x y + 120 y - 20 y^{2} - \frac{1}{10} x^{2} y - 90

extreme f(x,y)=2x^2+4y^2-2xy-10x-2y+2 extreme points

f (x, y) = 2 x^{2} + 4 y^{2} - 2 x y - 10 x - 2 y + 2

extreme f(x)=(7x)/(x^2+9),0<= x<= 9 extreme points

f (x) = \frac{7 x}{x ^{2} + 9}, 0 \leq x \leq 9

extreme 2x^3+4x^2-1 extreme points

2 x^{3} + 4 x^{2} - 1

extreme f(x)=x*(ln(x))^5 extreme points

f (x) = x \cdot (ln (x))^{5}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x+12)-8 ?
The extreme f(x)=sqrt(x+12)-8 is Minimum(-12,-8)